fix how Identifiers are evaluated
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fcdbd3139c
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4fc4d48412
@ -29,11 +29,21 @@ func (bctx BuildCtx) BuildStmt(s Statement) Expr {
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panicf("unknown macro: %q", m)
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}
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return fn(bctx, bctx.buildExpr(s.Arg))
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return fn(bctx, s.Arg)
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}
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// may return nil if e is a Statement which has no return
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func (bctx BuildCtx) buildExpr(e Expr) Expr {
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return bctx.buildExprTill(e, func(Expr) bool { return false })
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}
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// like buildExpr, but will stop short and stop recursing when the function
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// returns true
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func (bctx BuildCtx) buildExprTill(e Expr, fn func(e Expr) bool) Expr {
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if fn(e) {
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return e
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}
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switch ea := e.(type) {
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case llvmVal:
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return e
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@ -43,12 +53,12 @@ func (bctx BuildCtx) buildExpr(e Expr) Expr {
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if v, ok := bctx.C.GetIdentifier(ea); ok {
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return llvmVal(v)
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}
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return ea
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panicf("identifier %q not found", ea)
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case Statement:
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return bctx.BuildStmt(ea)
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case Tuple:
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for i := range ea {
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ea[i] = bctx.buildExpr(ea[i])
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ea[i] = bctx.buildExprTill(ea[i], fn)
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}
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return ea
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default:
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@ -66,15 +76,15 @@ func (bctx BuildCtx) buildVal(e Expr) llvm.Value {
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var globalCtx = &Ctx{
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macros: map[Macro]MacroFn{
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"add": func(bctx BuildCtx, e Expr) Expr {
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tup := e.(Tuple)
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tup := bctx.buildExpr(e).(Tuple)
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a := bctx.buildVal(tup[0])
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b := bctx.buildVal(tup[1])
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return llvmVal(bctx.B.CreateAdd(a, b, ""))
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},
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"bind": func(bctx BuildCtx, e Expr) Expr {
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tup := e.(Tuple)
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id := bctx.buildExpr(tup[0]).(Identifier)
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tup := bctx.buildExprTill(e, isIdentifier).(Tuple)
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id := bctx.buildExprTill(tup[0], isIdentifier).(Identifier)
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bctx.C.idents[id] = bctx.buildVal(tup[1])
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return nil
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},
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@ -95,6 +95,11 @@ func (id Identifier) equal(e equaler) bool {
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return ok && idid == id
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}
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func isIdentifier(e Expr) bool {
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_, ok := e.(Identifier)
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return ok
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}
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////////////////////////////////////////////////////////////////////////////////
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// Macro is an identifier for a macro which can be used to transform
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