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mlog: Add WithMaxLevel method

main
Brian Picciano 2 years ago
parent cbeee71cb1
commit ec5e2441c6
  1. 27
      mlog/mlog.go

@ -257,11 +257,19 @@ func (l *Logger) Close() error {
}
func (l *Logger) clone() *Logger {
l2 := *l
l2.l = new(sync.RWMutex)
l2.ns = make([]string, len(l.ns), len(l.ns)+1)
l2 := &Logger{
opts: &LoggerOpts{
MessageHandler: l.opts.MessageHandler,
MaxLevel: l.opts.MaxLevel,
Now: l.opts.Now,
},
l: new(sync.RWMutex),
ns: make([]string, len(l.ns), len(l.ns)+1),
}
copy(l2.ns, l.ns)
return &l2
return l2
}
// WithNamespace returns a clone of the Logger with the given value appended to
@ -273,9 +281,18 @@ func (l *Logger) WithNamespace(name string) *Logger {
return l
}
// WithMaxLevel returns a clone of the Logger with the given MaxLevel set as the
// value for the maximum log level which will be output (see MaxLevel in
// LoggerOpts).
func (l *Logger) WithMaxLevel(level int) *Logger {
l = l.clone()
l.opts.MaxLevel = level
return l
}
// Log can be used to manually log a message of some custom defined Level.
//
// If the Level is a fatal (Uint() == 0) then calling this will never return,
// If the Level is a fatal (Int() < 0) then calling this will never return,
// and the process will have os.Exit(1) called.
func (l *Logger) Log(msg Message) {
l.l.RLock()

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