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itertools .unique() doesn't require sorted items

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Alex Auvolat 2022-12-11 18:30:02 +01:00
parent ec12d6c8dd
commit 9d83364ad9
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1 changed files with 2 additions and 4 deletions
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6
src/rpc/layout.rs
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@ -353,20 +353,18 @@ To know the correct value of the new layout version, invoke `garage layout show`
// Check that every partition is associated to distinct nodes
let rf = self.replication_factor;
for p in 0..(1 << PARTITION_BITS) {
let mut nodes_of_p = self.ring_assignation_data[rf * p..rf * (p + 1)].to_vec();
nodes_of_p.sort();
let nodes_of_p = self.ring_assignation_data[rf * p..rf * (p + 1)].to_vec();
if nodes_of_p.iter().unique().count() != rf {
return Err(format!("partition does not contain {} unique node ids", rf));
}
// Check that every partition is spread over at least zone_redundancy zones.
let mut zones_of_p = nodes_of_p
let zones_of_p = nodes_of_p
.iter()
.map(|n| {
self.get_node_zone(&self.node_id_vec[*n as usize])
.expect("Zone not found.")
})
.collect::<Vec<_>>();
zones_of_p.sort();
let redundancy = self.parameters.zone_redundancy;
if zones_of_p.iter().unique().count() < redundancy {
return Err(format!(